50% of a radio active substance decays in 5 hours. The time required for the 87.5% decay is
A
10hours
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B
15hours
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C
12.5hours
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D
17.5hours
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Solution
The correct option is B15hours Now, it is given that half life of the radio active substance is 5 hours. Fraction of substance left after 87.5% decays =18 Let no of half-lifes passed be x, 18=(12)x⇒x=3