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Question

50% of a radio active substance decays in 5 hours. The time required for the 87.5% decay is

A
10hours
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B
15hours
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C
12.5hours
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D
17.5hours
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Solution

The correct option is B 15hours
Now, it is given that half life of the radio active substance is 5 hours.
Fraction of substance left after 87.5% decays =18
Let no of half-lifes passed be x,
18=(12)xx=3

So, 3 half lives i.e., 5×3 years =15 years

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