$50 %$ of X-rays obtained from a Coolidge tube pass through $0.3$ mm. thick aluminum foil. If the potential difference between the target and the cathode is increased, then the fraction of X-rays passing through the same foil will be :-

Question

Q.

50% of the X-ray coming from a Coolidge tube is able to pass through a 0.1 mm thick aluminium foil. If the potential difference between the target and the filament is increased, the fraction of the X-ray passing through the same foil will be

Answer 1

The penetration depth for any wave is proportional to

\frac{1}{λ}

, so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is

> 50

%

Answer 2

Hence, Option (B) is correct

50% of X-rays obtained from a Coolidge tube pass through 0.3mm. thick aluminum foil. If the potential difference between the target and the cathode is increased, then the fraction of X-rays passing through the same foil will be :-

The correct option is B >50%The penetration depth for any wave is proportional to 1λ, so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is >50%Hence, Option (B) is correct

The penetration depth for any wave is proportional to 1λ, so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is >50%

Hence, Option (B) is correct

$50 %$ of X-rays obtained from a Coolidge tube pass through $0.3$ mm. thick aluminum foil. If the potential difference between the target and the cathode is increased, then the fraction of X-rays passing through the same foil will be :-

The correct option is B $> 50 %$
The penetration depth for any wave is proportional to $\frac{1}{λ}$ , so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is $> 50$ %
Hence, Option (B) is correct

The penetration depth for any wave is proportional to $\frac{1}{λ}$ , so if we increase the voltage the wavelength decrease, so now more X-ray pass through the foil so answer is $> 50$ %