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Question

50 kg of N2 (g) and 10 kg of H2 are mixed to produce NH3 (g). Calculate the amount of NH3 (g) formed.
(assume the reaction goes to completion)
N2(g)+3H2(g)2NH3(g)

A
56.67 kg
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B
51.87 kg
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C
50.71 kg
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D
47.67 kg
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Solution

The correct option is A 56.67 kg
N2+3H22NH3
As per stoichiometry,
28 g of nitrogen reacts with 6 g of hydrogen.
So, 50 kg will react with 628×50 kg H2=10.7 kg
But, we have only 10 kg of H2
So, H2 is the limiting reagent.
6 g H2 gives 34 g NH3
10 kg H2 will give 346×10 =56.67 kg of NH3

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