50 volumes of hydrogen take 20 min of diffuse out of a vessel. If time required for 40 volumes of oxygen to diffuse out from the same vessel under the same conditions is $X$ min, then $X$ is__________.

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Solution

As we know,
$\frac{V_{1} / t_{1}}{V_{2} / t_{2}} = \sqrt{\frac{d_{2}}{d_{1}}} = \frac{50 / 20}{50 / t_{2}} = \sqrt{\frac{16}{1}}$
$\frac{5 \times t_{2}}{2 \times 40} = 4$
$∴ t_{2} = 64 m i n$

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