500 g of water at 60 deg-c is contained in a vessel of negligible heat capacity- Into this water is added 400 g of ice at 0 deg-c-Calculate the amount of ice which does not melt- Take S-H-C of water -4-2J-g- deg-c and sp- latent heat of ice -336 J-g-

Dear Student Qheat #160;gained #160;by #160;ice #160;=Qheat #160;lost #160;by #160;watermiceL #160;= #160;mwaterc #8710;Tmice=mwaterc #87 ...

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Standard VII

Chemistry

Evaporation

500 g of wate...

Question

500 g of water at 60°c is contained in a vessel of negligible heat capacity. Into this water is added 400 g of ice at 0°c.Calculate the amount of ice which does not melt?( Take S.H.C of water =4.2J/g/°c and sp. latent heat of ice =336 J/g)

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Solution

Dear Student

$Q_{h e a t g a i n e d b y i c e} = Q_{h e a t l o s t b y w a t e r} m_{i c e} L = m_{w a t e r} c ∆ T m_{i c e} = \frac{m_{w a t e r} c ∆ T}{L} m_{i c e} = \frac{(500) (4.2) (60 - 0)}{336} m_{i c e} = 375 g$
So mass of ice which melts is 375 gm.

So mass of ice doesn't melts = 400 -375 = 25 g.

Regards

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500 g of water at 60°c is contained in a vessel of negligible heat capacity. Into this water is added 400 g of ice at 0°c.Calculate the amount of ice which does not melt?( Take S.H.C of water =4.2J/g/°c and sp. latent heat of ice =336 J/g)

Dear Student Qheat gained by ice =Qheat lost by watermiceL = mwaterc∆Tmice=mwaterc∆TLmice=5004.260 -0336mice=375 g So mass of ice which melts is 375 gm. So mass of ice doesn't melts = 400 -375 = 25 g. Regards