Question

500 g of water at 80°C is mixed with 250 g of water at 50°C. Calculate the final temperature of the mixture.

Answer 1

Dear Student

$$\begin{gathered} Heatlost=heatgained \\ {m}_{1}s{t}_1+m_{2}s{t}_2=\left(m_1+m_2\right)st \\ Wheresisspecificheatofwater,tisfinaltemperatureofmixture \\ t=\frac{m_1{t}_1+m_2{t}_2}{\left(m_1+m_2\right)}=\frac{500\times 80+250\times 50}{500+250}=54.66{}^{o}C \end{gathered}$$