Question

500 gram of an aqueous solution of Urea is prepared by dissolving urea in 450 gram water . Find mass percentage of urea in this solution

Answer 1

Dear student,

Mass of Solution = 500 g

Mass of water = 450 g

Mass of Urea = x g

Mass of the solution = Mass of Urea + Mass of Water

500 = x g + 450g

x = 500 - 450

x = 50 gm

Concentration % (mass percent) = Mass of solute/Mass of solution x 100

= 50/500 x 100

= 5000/500

= 10%

Regards