$500$ ml aqueous solution is prepared by dissolving $2$ moles of $H C l$ in water. What will be the molarity of this solution ?

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Solution

The correct option is C 4
Given conditions ⇒

Volume of the Aqueous solution = 500 mL.

No. of moles of HCl = 2 moles.

∵ Molarity = No. of moles/Volume in mL × 1000

∴ Molarity = 2/500 × 1000

= 4 M.

Hence, the molarity of the solution is 4 M.

Hence, option (D) is correct.

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Similar questions

500 my aqueous solution is prepared by dissolving 2 moles of hcl in water. What will be the molarity of this solution.

N a O H

0.4 m o l e s

0.2 m o l e s

C a C l_{2}

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