500 ml of a gaseous hydrocarbon when burnt in excess of o2 gave 2.5 lt of co2 and 3lt of h2o vapours under same conditions. molecular formula of the hydrocarbon is ? a)c4h8 b)c4h10 c)c5h10 d)c5h12

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500 m L

of a gaseous hydrocarbon when burnt in excess of

O_{2}

gave

2.5 L

C O_{2}

and

3.0 L

of water vapour under same conditions. The molecular formula of the hydrocarbon is :

15 ml of a gaseous hydrocarbon required 75 ml of O2 for complete combustion and it produced 45 ml of CO2 (All volumes are measured under identical conditions).The hydrocarbon is

a)C5H12 b)C3H6 c)C4H10 d)C3H8

Q. 100 ml of a hydrocarbon on combustion gave

300 m l o f C O_{2}

and 400 ml of water vapour, measured under similar conditions of temperature and pressure. The molecular formula of hydrocarbon is:

Q. 40 ml of hydrocarbon on combustion gave 120 ml

C O_{2}

and 80 mI water vapour. The molecular formula of hydrocarbon is:

Q. 100 ml of a hydrocarbon on combustion gave 300 ml of

C O_{2}

and 400 ml of water vapor measured under similar conditions of temperature and pressure. Find out the molecular formula of hydrocarbon.

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