Question

$500$ mL of a glucose solution contains $6.02\times {10}^{22}$ molecules. The concentration of the solution is:

• A. $0.1M$
• B. $1.0M$
• C. $0.2M$
• D. $2.0M$

Answer 1

The correct option is C $0.2M$

The number of moles of glucose is $\frac{6.02\times {10}^{22}}{6.02\times {10}^{23}}=0.1$ mol.

A total volume of the solution $=500$ mL.

Hence, $1000$ mL of solution will contain $0.2$ moles.

Molarity$=\frac{noofmoles}{Volumeinlitre}$

$=\frac{02}{1}$ mole/ L

Hence, the concentration of the solution is $0.2M$.

Hence, the correct option is $C$