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Carbohydrates

500 mL of chl...

Question

500 mL of chlorine contaminated water is treated with $K I$ and mixture required 100 mL of 0.01 M hypo. What is concentration of $C l_{2}$ in millimoles per litre?

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Solution

$C l_{2} + 2 K I \to I_{2} + 2 K C l$
$2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I$
Thus 1 mole of chlorine corresponds to 2 moles of $2 N a_{2} S_{2} O_{3}$ .
The number of millimoles of hypo solution are $0.01 M \times 100 m l = 1$
The number of millimiles of chlorine are $\frac{1}{2} = 0.5$ millimoles
Thus, the concntration of chlorine is $\frac{0.5 m i l l i m o l e s}{500 m L} \times 1000 m L / L = 1 m i l l i m o l e / L$

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