Question

$500mL$ of a glucose solution contains $6.02\times {10}^{22}$ molecules. The concentration of the solution is

• A. $0.1M$
• B. $1.0M$
• C. $0.2M$
• D. $2.0M$

Answer 1

The correct option is C $0.2M$

Given, $500ml$ $C_6{H}_{12}{O}_6$ contains $6.02\times {10}^{22}$ molecules

We know $1$ mole of $C_6{H}_{12}{O}_6$ contains $6.02\times {10}^{23}$ molecules

$\therefore$ No. of moles having $6.02\times {10}^{22}$ molecules=$\frac{6.02\times {10}^{22}}{6.02\times {10}^{23}}=0.1$ moles

Now, Molarity=$\frac{No.ofmoles}{VinL}=\frac{0.1mol}{0.5L}=0.2M$

Concentration of solution=$0.2M$.