500mL of HCl of pH4.3010 is allowed to react with 500mL of pH9.6990NaOH solution at 300K. If temperature remains constant, approximate pH of resulting solution is:
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Solution
For NaOH solution,
pOH=14−pOH
=14−9.6990
=4.3010. Thus the pH of HCl is equal to pOH of NaOH. Also, the volumes of the two solutions are equal. Hence, the number of moles of hydrogen ions present in HCl is equal to the number of moles of hydroxide ions present in NaOH. Thus, two solutions will completely neutralize each other. The pH of the resulting solution will be 7.