50g of copper is heated to increase its temperature by $10^{o} C$ . If the same quantity of heat is given to 10 g of water, the rise in its temperature is :
(Specific heat of copper $=$ 420J/kg $^{o} C$ ; Specific heat of water $=$ 4200J/kg $^{o} C$ )

5^{o} C

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6^{o} C

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7^{o} C

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8^{o} C

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Solution

The correct option is A $5^{o} C$
Amount of heat given to copper $=$ Amount of heat given to water
$m_{c} . C_{c} . Δ T_{1} = m_{w} . C_{w} . Δ T_{2}$
$(50) (0.42) (10) = (10) (4.2) Δ T_{2}$
$Δ T_{2} = 5^{o} C$

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Similar questions

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is (specific heat of copper = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

50 g

of copper is heated to increase its temperature by

10^{\circ} C

. If the same quantity of heat is given to

10 g

of water, then the rise in its temperature is (specific heat of copper

= 420 J / k g /^{\circ} C

)

Q. 50 g of copper is heated to increase its temperature by

10^{o} C

. If the same quantity of heat is given to 10 g of water, the rise in temperature is

(s p e c i f i c h e a t o f c o p p e r = 420 J k g^{- 1} K^{- 1}, s p e c i f i c h e a t o f w a t e r = 4200 J k g^{- 1} K^{- 1})

$400 g$ of iron is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $200 g$ of water, the rise in its temperature is ___ $^{\circ} C$ (specific heat of iron = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

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50g of copper is heated to increase its temperature by 10oC. If the same quantity of heat is given to 10 g of water, the rise in its temperature is :(Specific heat of copper = 420J/kgoC ; Specific heat of water = 4200J/kgoC )

The correct option is A 5oCAmount of heat given to copper=Amount of heat given to watermc.Cc.ΔT1=mw.Cw.ΔT2(50)(0.42)(10)=(10)(4.2)ΔT2ΔT2=5oC

50g of copper is heated to increase its temperature by $10^{o} C$ . If the same quantity of heat is given to 10 g of water, the rise in its temperature is :
(Specific heat of copper $=$ 420J/kg $^{o} C$ ; Specific heat of water $=$ 4200J/kg $^{o} C$ )

The correct option is A $5^{o} C$
Amount of heat given to copper $=$ Amount of heat given to water
$m_{c} . C_{c} . Δ T_{1} = m_{w} . C_{w} . Δ T_{2}$
$(50) (0.42) (10) = (10) (4.2) Δ T_{2}$
$Δ T_{2} = 5^{o} C$