50g of saturated solution of NaCl at 300C is evaporated to dryness and 13.2g of dry NaCl was obtained. Find the solubility of NaCl at 300C in water.
36 g
Mass of water in solution = 50-13.2 = 36.8g
Solubility of NaCl= Mass of NaClMass of water×100⇒13.236.8×100⇒36gm
Solubility of NaCl = 36g (approx.)