50J heat is supplied to a gaseous system simultaneously the gas expands against external pressure 2atm by 0.8L. The change in internal energy of the system will be:
A
−120.8J
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B
−112.11J
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C
−125.4J
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D
−130.60J
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Solution
The correct option is B−112.11J Solution:- (B) −112.11J
Given that the heat is supplied to the system.
Therefore,
q=50J
Given:-
Pext.=2atm
ΔV=0.8L
As we know that,
w=−PΔV
⇒w=−2×0.8=−1.6L−atm=−162.11J
Now from first law of thermodynamics,
ΔU=q+w
⇒ΔU=50+(−162.128)=−112.11J
Hence the change in internal energy of the system will be −112.11J.