$50 m L$ of $0.10 M$ ${N a}_{3} {P O}_{4} + 50 m L$ of $0.10 M$ $N a H_{2} O_{4}$ .

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Solution

For $H_{2} {C O}_{3} \to k_{1} = 4.2 \times 10^{- 7}, k_{2} = 4.8 \times 10^{- 11}$
$H_{3} {P O}_{4} \to k_{1} = 7.5 \times 10^{- 3}, k_{2} = 6.2 \times 10^{- 8}, k_{3} = 10^{- 12}$
${N a}_{3} {P O}_{4} 5 - + H C l 5 - ⟶ {2 N a}_{2} {H P O}_{4} 10$
$p H = \frac{p k_{2} + p k_{3}}{2} = 9.6$

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