50ml of water takes 5min to evaporate from a vessel on a heater connected to an electric source which delivers 400W .the enthalpy of vaporisation of water is?

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Solution

Dear Student,

$Energy consumption in 1 \sec = 400 J Energy consumption in 5 \min i . e . 5 \times 60 = 300 \sec = 400 \times 300 = 120 kJ ∆ H_{vap} = \frac{120}{(50 / 18)} = 43.2 kJ / mol$

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50ml of water takes 5min to evaporate from a vessel on a heater connected to an electric source which delivers 400W .the enthalpy of vaporisation of water is?

Dear Student, Energy consumption in 1 sec = 400 JEnergy consumption in 5 min i.e. 5×60 =300 sec =400×300= 120 kJ∆Hvap=120(50/18)=43.2 kJ/mol

Dear Student,

$Energy consumption in 1 \sec = 400 J Energy consumption in 5 \min i . e . 5 \times 60 = 300 \sec = 400 \times 300 = 120 kJ ∆ H_{vap} = \frac{120}{(50 / 18)} = 43.2 kJ / mol$