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Introduction to Inorganic Chemistry

51. In the co...

Question

51. In the complex with formula $M C l_{3} \cdot 4 H_{2} O$ , the coordination number of the metal M is six and there is no molecule of hydration in it. The volume of $0.1 M A g N O_{3}$ solution needed to precipitate the free chloride ions in 200 ml., of 0.01 M solution of the complex is:

40 mL

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20 mL

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60 mL

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80 mL

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Solution

The correct option is B 20 mL
The complex will be: $[M (H_{2} O)_{4} C l_{2}] C l$ ,
the complex have free chloride ion concentration of $(0.01 M) .$
$1 C l^{-} + 1 A g N O_{3} \to A g C l + N O_{3}^{-}$
$\frac{M_{1} V_{1}}{n_{1}} = \frac{M_{2} V_{2}}{n_{2}}$ or $\frac{0.01 \times 200}{1} = \frac{0.1 \times V_{2}}{1}$
$V_{2} = 20 m L$

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