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Heisenberg Uncertainty Principle

51 The probab...

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51 The probability of finding a 1s electron is maximum A at the nucleus B at the Bohr radius C at a large distance from the nucleus D in between the nucleus and the first Bohr orbit

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Q. The wave function for

1 s

orbital of the hydrogen atom is given by

Ψ_{1 s} = \frac{π}{\sqrt{2}} e^{- r / a_{0}}

a_{0} =

Radius of first Bohr orbit

r =

Distance from the nucleus (Probability of finding the electron varies with respect to it)

What will be the ratio of probabilities of finding the electrons at the nucleus to first Bohr's orbit

a_{0}

Q. What are the average distance and the most probable distance of an electron from the nucleus in the 1s orbital of a hydrogen atom?

(a_{0}

=the radius of the first Bohr orbit)

Q. The first orbital of H is represented by:

Ψ = \frac{1}{\sqrt{π}} {[\frac{1}{a_{0}}]}^{3 / 2} e^{- r / a_{0}}

a_{0}

is Bohr orbit. The probability of finding the electron at a distance 'r' from the nucleus is:

Q. For 1s orbital of hydrogen atom, the radial electron probability has a maximum value from its nucleus, at a distance of:

Q. For an electron in a hydrogen atom, the wave function

Ψ

is proportional to exp, where

a_{0}

is the Bohrs radius. What is the ratio of the probability of finding the electron at the nucleus to the probability of finding it at

a_{0}

?

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