Question

(5,12,x) form a Pythagorean triplet where x is largest . Find the value of x.

Answer 1

$$\begin{gathered} \mathrm{Hi}, \\ \mathrm{we}\mathrm{know}\mathrm{that}\mathrm{pythagorean}\mathrm{triplet}\mathrm{folllow},\mathrm{pythagorus}\mathrm{theorem}\mathrm{so} \\ \mathrm{if}\mathrm{x}\mathrm{is}\mathrm{largetst}\mathrm{then}\mathrm{it}\mathrm{is}\mathrm{hypotenuse}\mathrm{so} \\ {\mathrm{hypotenuse}}^2={\mathrm{base}}^2+{\mathrm{altitude}}^2 \\ {\mathrm{x}}^2=5^2+{12}^2 \\ {\mathrm{x}}^2=169 \\ \mathrm{x}=\sqrt{169}=13\mathrm{unit} \end{gathered}$$