Question

(-5,2), (3, -6) and (7, 4) are vertices of a triangle find the length of its median through vertex (3, -6).

Answer 1

D is the mid point of BC
$D=(\frac{7-5}{2},\frac{4+2}{2})D=(1,3)AD=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}=\sqrt{(1-3{)}^2+(3+6{)}^2}=\sqrt{4+81}=\sqrt{84}$