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Byju's Answer
Standard XII
Chemistry
Concentration Terms
520 gm mixtur...
Question
520 gm mixture of
F
e
2
O
3
and FeO reacts completely with 158 gm
K
M
n
O
4
in acidic medium. Calculate the mole % of
F
e
2
O
3
in mixture.
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Solution
Only
F
e
O
with
K
M
n
O
4
5
F
e
2
−
+
M
n
O
−
4
→
M
n
2
+
+
5
F
e
3
+
+
4
H
2
O
+
8
H
+
n of
K
M
n
O
4
=
158
158
=
1
m
o
l
∴
F
e
2
+
=
5
m
o
l
∴
F
e
O
=
5
m
o
l
Mass
=
72
×
5
=
360
g
Mass of
F
e
2
O
3
=
160
g
Mole =
160
160
=
1
m
o
l
e
∴
mol % =
1
6
×
100
=
50
3
%
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