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Concentration Terms

520 gm mixtur...

Question

520 gm mixture of ${F e}_{2} O_{3}$ and FeO reacts completely with 158 gm $K M n O_{4}$ in acidic medium. Calculate the mole % of ${F e}_{2} O_{3}$ in mixture.

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Solution

Only $F e O$ with $K M n O_{4}$
$5 F e^{2 -} + M n O_{4}^{-} \to M n^{2 +} + 5 F e^{3 +} + 4 H_{2} O + 8 H^{+}$
n of $K M n O_{4} = \frac{158}{158} = 1 m o l$
$∴ F e^{2 +} = 5 m o l$
$∴ F e O = 5 m o l$
Mass $= 72 \times 5$
$= 360 g$
Mass of $F e_{2} O_{3} = 160 g$
Mole = $\frac{160}{160} = 1 m o l e$
$∴$ mol % = $\frac{1}{6} \times 100 = \frac{50}{3}$ %

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