54 is divided into 2 parts such that the sum of 10 times the first part and 22 times the second part is 780. The bigger number is ----
34
Let the first part be x and the second part be y
⇒ x + y = 54 ......(i) and 10x + 22y = 780 .......(ii)
solving the above equations we get
From (i) x = 54 - y, substituting x in (ii)
10(54 - y) + 22y = 780
⇒ 12y = 240 oy y = 20
⇒ x = 34
The bigger part is 34