55 cows can graze a field in 16 days.
How many cows will graze the same field in 10 days?
Let number of cows required = x
Therefore:
Cows55xPeriod (in days)1610
Less days, more cows
∴ By inverse variation:
55:x=10:16⇒55x=1016⇒10x=16×55⇒x=16×5510=88
∴ Number of cows = 88