Question

550 kJ cycle-1 work is done by 1 mol of an ideal gas in a cyclic process. The amount of heat absorbed by the system is one cycle is

Answer 1

The amount of heat absorbed by system would be negative of work done. As the work done is by the gas, so it is negative so the heat absorbed will be positive. ∆u=q+w
​​​​​​∆u =0 for cyclic process q=-w
q=-(-550) kj
q=550 kj
550 kj is the amount of heat absorbed by the system in one cycle.