Here the rule which is applicable on the series: nbsp;56 nbsp;210 nbsp;462 nbsp;812 is Rule nbsp;C. Add the number to its square nbsp;as: 7 ^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sigma n3

56 210 462 ...

Question

$56210462812$

Open in App

Solution

Here the rule which is applicable on the series: 56 210 462 812 is Rule C. Add the number to its square as:
$7^{2} + 7 = 56, 14^{2} + 14 = 210, 21^{2} + 21 = 462 a n d 28^{2} + 28 = 812$
Hence, Rule (C) is the correct answer.

Suggest Corrections

Join BYJU'S Learning Program