$_{26}^{56} F e ⟶ 2 (_{13}^{28} A l) m_{F e} = 55.93494 m_{A l} = 27.98191$
Find Q value of reaction. Is fission energetically possible?

-27 MeV, Yes

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27 MeV, No

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15 MeV, Yes

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-15 MeV, No

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Solution

The correct option is B 27 MeV, No
Since transformation is to a less stable nucleus, hence reaction is not possible.

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Similar questions

Q. Suppose, we think of fission of a

_{26}^{56} F e

nucleus into two equal fragments of

_{13}^{28} A l

. Is the fission energetically possible? Argue by working out Q of the process. Given m

(_{26}^{56} F e)

= 55.93494 u and m

(_{13}^{28} A l)

= 27.98191 u.

Q. Suppose, we think of fission of a 5626Fe nucleus into two equalfragments, 2813 Al . Is the fission energetically possible? Argue byworking out Q of the process. Given m ( 5626Fe ) = 55.93494 u andm ( 2813 Al ) = 27.98191 u.

_{26}^{56} F e ⟶ 2 (_{13}^{28} A l) m_{F e} = 55.93494 m_{A l} = 27.98191

Find Q value of reaction. Is fission energetically possible?

Calculate the Q-value of the fusion reaction $^{4} H e +^{4} H e =^{8} B e$ Is such a fusion energetically favorable? Atomic mass of $^{8} B e$ is 8.0053 u and that of $^{4} H e$ is 4.0026 u.

Suppose, we think of fission of a nucleus into two equal fragments,. Is the fission energetically possible? Argue by working out Q of the process. Given and.

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5626Fe⟶2(2813Al)mFe=55.93494mAl=27.98191 Find Q value of reaction. Is fission energetically possible?

The correct option is B 27 MeV, NoSince transformation is to a less stable nucleus, hence reaction is not possible.

$_{26}^{56} F e ⟶ 2 (_{13}^{28} A l) m_{F e} = 55.93494 m_{A l} = 27.98191$
Find Q value of reaction. Is fission energetically possible?

The correct option is B 27 MeV, No
Since transformation is to a less stable nucleus, hence reaction is not possible.