56 − 37 = $?$

10 + 10 − 1 = ______

So 56 − 37 =

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Solution

10 + 10 − 1 = 19
So,
56 − 37 = $19$

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\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})

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\frac{4}{1!} + \frac{11}{2!} + \frac{22}{3!} + \frac{37}{4!} + \frac{56}{5!} + . . . \infty = b e - 1

\frac{4}{1!} + \frac{11}{2!} + \frac{22}{3!} + \frac{37}{4!} + \frac{56}{5!} + . . . \infty = 6 e - 1

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