Question

$56$ litre of ozone gas contains:

• A. $7.5$ mole of ozone gas
• B. $2.5$ mole of oxygen atoms
• C. $2.5$ mole of ozone gas
• D. $2.5$ $N_A$ oxygen atoms

Answer 1

The correct option is C $2.5$ mole of ozone gas

For any gas $22.4L$ volume is occupied by $=1mole$

$56L$ will be occupied by$=\frac{56}{22.4}=2.5mole$ of ozone gas.

1 molecule of Ozone $O_3$ has 3 atoms of $O$

$2.5mole{O}_3$ has $=2.5\times 3=7.5$mole of oxygen atoms

or $7.5N_A$ oxygen atoms