Question

$561d{m}^3$ fo a gas at S.T.P. is filled in a $748d{m}^3$ container. If temperature is constant, calculate th epercentage change in pressure required.

Answer 1

Initial volume=

$P_1$ = 760
Final volume = $V_2$ = 748 $d{m}^3$

$P_1{V}_1$ = $P_2{V}_2$

760 $\times$ 561 = $P_2$ $\times$ 748

$P_2$ = $\frac{760\times 561}{748}$ = 570

So, Initial pressure was 760mm
Changed pressure is 570mm
Therefore % change = $\frac{760-570}{760}\times 100=\frac{190\times 100}{760}$ = 25%