The surface area of a cuboid of dimensions 10 m x 12 m x 8 m is
Add 213 to the reciprocal of −2612.
m3−14m2+37m−26 by m2−12m+13
x2 + y2 − 4x + 6y − 12 = 0 and x2 + y2 + 6x + 18y + 26 = 0 __________.