59.The value of cos inverse (4/5) + tan inverse (3/5) is equal to (1) tan inverse (27/11) (2) sin inverse (11/27) (3) cos inverse (11/27) (4) zero

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{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

{t a n}^{- 1} \frac{1}{2} + {t a n}^{- 1} \frac{1}{3} = \frac{π}{4}

{t a n}^{- 1} \frac{1}{2} + {t a n}^{- 1} \frac{1}{5} + {t a n}^{- 1} \frac{1}{8} = \frac{π}{4}

{t a n}^{- 1} \frac{3}{4} + {t a n}^{- 1} \frac{3}{5} - {t a n}^{- 1} \frac{8}{19} = \frac{π}{4}

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

2 {t a n}^{- 1} \frac{1}{5} + {s e c}^{- 1} \frac{5 \sqrt{2}}{7} + 2 {t a n}^{- 1} \frac{1}{8} = \frac{π}{4}

{c o s}^{- 1} \frac{12}{13} + 2 {c o s}^{- 1} \sqrt{(\frac{64}{65})} + {c o s}^{- 1} \sqrt{(\frac{49}{50})} = {c o s}^{- 1} \frac{1}{\sqrt{2}}

{cos}^{- 1} (cos (- 5)) + {sin}^{- 1} (sin (6)) - {tan}^{- 1} (tan (12))

{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

{t a n}^{- 1} x + {t a n}^{- 1} y = {t a n}^{- 1} \frac{x + y}{1 - x y}

x y < 1

π + {t a n}^{- 1} \frac{x + y}{1 - x y}

x y > 1

3 {t a n}^{- 1} (\frac{1}{2}) + 2 {t a n}^{- 1} (\frac{1}{5}) + {s i n}^{- 1} \frac{142}{65 \sqrt{5}}

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