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Byju's Answer
Standard XII
Mathematics
Conjugate of a Complex Number
5A1 - 23A = 3...
Question
5
A
1
−
23
A
=
325
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Solution
1
−
A
=
5
?
i.e.
11
−
A
=
5
,
Therefore
A
=
6
or
(
500
+
10
A
+
1
)
−
(
200
+
30
+
A
)
=
325
501
−
230
+
10
A
−
A
=
325
271
+
9
A
=
325
271
+
9
A
=
325
271
−
271
=
9
A
=
325
−
271
9
A
=
54
A
=
6
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