$5 c m$ high object is placed at a distance of $25 c m$ from a converging lens of focal length $10 c m$ . Determine the position, size and also type of the image.

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Solution

$f = + 10 c m$
$u = - 25 c m$
$\frac{1}{V} - [\frac{- 1}{25}] = \frac{1}{10}$
$\frac{1}{V} = \frac{1}{10} - \frac{1}{25}$
$= \frac{15}{250} = \frac{3}{50}$
$V = \frac{50}{3} c m$

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5cm high object is placed at a distance of 25cm from a converging lens of focal length 10cm. Determine the position, size and also type of the image.

f=+10cmu=−25cm1V−[−125]=1101V=110−125=15250=350V=503cm

$5 c m$ high object is placed at a distance of $25 c m$ from a converging lens of focal length $10 c m$ . Determine the position, size and also type of the image.

$f = + 10 c m$
$u = - 25 c m$
$\frac{1}{V} - [\frac{- 1}{25}] = \frac{1}{10}$
$\frac{1}{V} = \frac{1}{10} - \frac{1}{25}$
$= \frac{15}{250} = \frac{3}{50}$
$V = \frac{50}{3} c m$