5g of a crystalline salt lost 1.8g of water on heating, it's formula weight (anhydrous salt) is 160. The water of crystallisation of the salt is.

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Solution

3.2 g of anhydrous salt requires 1.8 g of water to become crystalline
160 g of salt requires $\frac{160 \times 1.8}{3.2}$ g of water.
$∴$ The amount of water corresponding to 160 g of the salt $= \frac{160 \times 1.8}{3.2}$ = $90.0$ g
Number of water molecules = $\frac{90}{18}$ = $5$

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Q. 5g of a crystalline salt lost 1.8g of water on heating, it's formula weight (anhydrous salt) is 160. The water of crystallisation of the salt is.

5

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1.89

g of water. The formula weight of anhydrous salts is

160

. The number of molecules of water of crystallisation in the salt is:

5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of crystallization is:

5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of

crystallization is

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5g of a crystalline salt lost 1.8g of water on heating, it's formula weight (anhydrous salt) is 160. The water of crystallisation of the salt is.

3.2 g of anhydrous salt requires 1.8 g of water to become crystalline 160 g of salt requires 160×1.83.2 g of water. ∴ The amount of water corresponding to 160 g of the salt =160 × 1.83.2 = 90.0 g Number of water molecules =9018 = 5

3.2 g of anhydrous salt requires 1.8 g of water to become crystalline
160 g of salt requires $\frac{160 \times 1.8}{3.2}$ g of water.
$∴$ The amount of water corresponding to 160 g of the salt $= \frac{160 \times 1.8}{3.2}$ = $90.0$ g
Number of water molecules = $\frac{90}{18}$ = $5$