5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of crystallization is:

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Solution

The correct option is D
5

(5-1.8) g of salt require 1.8 g of water

160g of salt requires $\times$ g of water.

= $\frac{160 \times 1.8}{3.2}$ = $90.0 g$

No. of water molecules = $\frac{90}{18}$ = $5.$

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5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of crystallization is:

5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of

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g of crystalline salt, when rendered anhydrous, lost

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Q. 5g of a crystalline salt lost 1.8g of water on heating, it's formula weight (anhydrous salt) is 160. The water of crystallisation of the salt is.

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5g of crystalline salt rendered anhydrous; lost 1.8g of water. The formula weight of the anhydrous salts is 160. The number of water molecules of crystallization is:

The correct option is D 5 (5-1.8) g of salt require 1.8 g of water 160g of salt requires × g of water. = 160 × 1.83.2 = 90.0g No. of water molecules =9018 = 5.

The correct option is D
5

(5-1.8) g of salt require 1.8 g of water

160g of salt requires $\times$ g of water.

= $\frac{160 \times 1.8}{3.2}$ = $90.0 g$

No. of water molecules = $\frac{90}{18}$ = $5.$