Question

(5p²-25p+20) divided by
(p-1)

Answer 1

$$\begin{gathered} \frac{5{\mathrm{p}}^2-25\mathrm{p}+20}{\mathrm{p}-1} \\ =\frac{5\left[{\mathrm{p}}^2-5\mathrm{p}+4\right]}{\mathrm{p}-1} \\ =\frac{5\left[{\mathrm{p}}^2-4\mathrm{p}-\mathrm{p}+4\right]}{\left(\mathrm{p}-1\right)} \\ =\frac{5\left[\mathrm{p}\left(\mathrm{p}-4\right)-1\left(\mathrm{p}-4\right)\right]}{\left(\mathrm{p}-1\right)} \\ =\frac{5\left(\mathrm{p}-1\right)\left(\mathrm{p}-4\right)}{\left(\mathrm{p}-1\right)} \\ =5\left(\mathrm{p}-4\right) \end{gathered}$$