5t – 3 = 3t – 5 ⇒ 5t 3t = 5 +3 ⇒ 2t = 2 ⇒ t= 2/2= 1 To Check: 5t 3 =3t 5 ⇒ 5 × ( 1) 3=3 × ( 1) 5 ⇒ 5 3= 3 5 ⇒ 8= 8 ⇒ L.H.S=R.H.S Hence, it is correct. ...

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Standard IX

Mathematics

Mathematical Statements

Question 25 t...

Question

Question 2
5t – 3 = 3t – 5

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Solution

5t – 3 = 3t – 5
$\Rightarrow 5 t - 3 t = - 5 + 3$
$\Rightarrow 2 t = - 2$
$\Rightarrow t = \frac{- 2}{2} = - 1$
To Check:
$5 t - 3 = 3 t - 5 \Rightarrow 5 \times (- 1) - 3 = 3 \times (- 1) - 5$
$\Rightarrow - 5 - 3 = - 3 - 5 \Rightarrow - 8 = - 8$
$\Rightarrow L . H . S = R . H . S$
Hence, it is correct.

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Similar questions

Q. Question 2
5t – 3 = 3t – 5

Q. Simplify

(5 t^{2})^{2} \div (25 t)^{3 / 2} \times (5 t^{1 / 2})^{3}

and find the power of

t

to closest integer.

Q. A wave is represented by

y_{1} = 10 cos (5 x + 25 t)

, where

x

and

y

are measured in

centimetres

and

t

seconds

. A second wave for which

y_{2} = 20 cos (5 x + 25 t + π / 3)

interferes with the first wave. Find the amplitude and phase of the resultant wave.

Q. A wave is represented by

y_{1} = 10 c o s (5 x + 25 t)

where, x is measured in metres and t in seconds. A second wave for which

y_{2} = 20 c o s (5 x + 25 t + \frac{π}{3})

interferes with the first wave. Deduce the amplitude and phase of the resultant wave.

Q. Factorise:

5 t + 25 t^{2}

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Mathematical Statements

Standard IX Mathematics

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Question 2 5t – 3 = 3t – 5

5t – 3 = 3t – 5 ⇒5t−3t=−5+3 ⇒2t=−2 ⇒t=−22=−1 To Check: 5t−3=3t−5⇒5×(−1)−3=3×(−1)−5 ⇒−5−3=−3−5⇒−8=−8 ⇒L.H.S=R.H.S Hence, it is correct.

Question 2
5t – 3 = 3t – 5