$5 x - 2 y + 4 = 0$ is a linear equation. Write another equation in two variables such that the geometrical representation of the pair so formed are intersecting lines.

10 x - 4 y + 3 = 0

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7 x + 6 y - 9 = 0

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20 x - 8 y + 3 = 0

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Data insufficient

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Solution

The correct option is C $7 x + 6 y - 9 = 0$
For the given condition
$\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$
Then the second equation will be
$7 x + 6 y - 9 = 0$
Here $\frac{a_{1}}{a_{2}} = \frac{5}{7}, \frac{b_{1}}{b_{2}} = \frac{- 2}{6}$
Hence $\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$

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5 x - 2 y + 4 = 0

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5x−2y+4=0 is a linear equation. Write another equation in two variables such that the geometrical representation of the pair so formed are intersecting lines.

The correct option is C 7x+6y−9=0For the given conditiona1a2≠b1b2Then the second equation will be7x+6y−9=0Herea1a2=57,b1b2=−26Hence a1a2≠b1b2

$5 x - 2 y + 4 = 0$ is a linear equation. Write another equation in two variables such that the geometrical representation of the pair so formed are intersecting lines.

The correct option is C $7 x + 6 y - 9 = 0$
For the given condition
$\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$
Then the second equation will be
$7 x + 6 y - 9 = 0$
Here $\frac{a_{1}}{a_{2}} = \frac{5}{7}, \frac{b_{1}}{b_{2}} = \frac{- 2}{6}$
Hence $\frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}}$