The given system of equation is:
5x - 3y - 1 = 0 ……(i)
2x + 5y - 19 = 0 ……(ii)
On multiplying (i) by 2 and (ii) by 5, we get:
10x - 6y = 2 ……(iii)
10x + 25y = 95 …….(iv)
On substacting (iii) from (iv) we get:
31y = (95 - 2) = 93
⇒y= 3
On substituting the value of y=3 in (i), we get:
5x – 9 – 1 = 0
⇒5x = (9+1) = 10
⇒x = 2
Hence, the solution is x = 2 and y = 3