Question

$5y^2+5y-10$.

Answer 1

In the given polynomial $5y^2+5y-10$,

The first term is $5y^2$ and its coefficient is $5$.

The middle term is $5y$ and its coefficient is $5$.

The last term is a constant term $-10$.

Multiply the coefficient of the first term by the constant $5\times -10=-50$.

We now find the factor of $-50$ whose sum equals the coefficient of the middle term, which is $5$ and then factorize the polynomial $5y^2+5y-10$ as shown below:

$5y^2+5y-10=5y^2-5y+10y-10=5y(y-1)+10(y-1)=(5y+10)(y-1)=5(y+2)(y-1)$

Hence, $5y^2+5y-10=5(y+2)(y-1)$.