Question

$6.022\times {10}^{20}$ atoms of silver (at mass = 108 u) weigh

• A. $108\times {10}^{3}g$
  
• B. $108g$
• C. $0.108g$
• D. $10.8g$

Answer 1

The correct option is C $0.108g$

The gram atomic mass of silver =108g

Since - 108g of Ag is equal to 1 mole of Ag

$\therefore$ $6.023\times {10}^{23}$ atoms of Ag are contained by = 108 g of Ag

$6.023\times {10}^{20}$ atoms will be contained by $\frac{108}{6.023\times {10}^{23}}\times 6.023\times {10}^{20}=0.108g$