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Concentration Terms

6.10 gram of ...

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6.10 gram of impure naoh is completely neutralized by 1000 ml of 1/10n hcl .calculate the percentage purity of the impure naoh

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2.26 g

of impure ammonium chloride were boiled with

100 m L

N N a O H

solution till no more ammonia was given off. The excess of

N a O H

solution left over required

30 m L 2 N H_{2} S O_{4}

for neutralisation. Calculate the percentage purity of the salt.

Q. 1000 g impure sample of NaOH contains 3 mol of oxygen atoms. The

%

purity of the sample is:

1 M N a O H

solution was slowly added into

1000

183.75

H_{2} S O_{4}

solution and the following plot was obtained. The percentage purity of

H_{2} S O_{4}

sample and slope of the curve respectively, are

0.80 g

(N H_{4})_{2} S O_{4}

was boiled with

100 m l

0.2 N NaOH

solution till all the

N H_{3} (g)

evolved.The remaining solution was diluted to

250 mL.25 mL

of this solution was neutralized using

5 m L

0.2 n H_2SO_4

solution.The percentage purity of the

(N H_{4})_{2} S O_{4}

3.0 g

of a sample of impure ammonium chloride were boiled with an excess of caustic soda solution. Ammonia gas so evolved was passed into

120 m L

N / 2 H_{2} S O_{4}

28 m L

N / 2 N a O H

were required to neutralize residual acid. Calculate the percentage of purity of the given sample of ammonium chloride.

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