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Odd and Even Numbers

6, 13, 25, 51...

Question

$6, 13, 25, 51, 101, ?$

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Solution

The pattern is $\times 2 + 1, \times 2 - 1, \times 2 + 1, \times 2 - 1$
Hence, the next term is $101 \times 2 + 1 = 203$ .

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Similar questions

\frac{2 x - 1}{3} - \frac{6 x - 2}{5} = \frac{1}{3}

When $4^{101} + 6^{101}$ is divided by $25$ , the remainder is:

b_{i} > 1

l o g_{e} b_{1}, l o g_{e} b_{2}, \dots \dots l o g_{e} b_{101}

l o g_{e} 2

a_{1}, a_{2}, \dots \dots a_{101}

a_{1} = b_{1}

a_{51} = b_{51}

t = b_{1} + b_{2} + \dots \dots + b_{51}

s = a_{1} + a_{2} + \dots \dots + a_{51}

b_{i} > 1 for i = 1, 2, . . ., 101.

{log}_{e} b_{1}, {log}_{e} b_{2}, . . ., {log}_{e} b_{101}

{log}_{e} 2.

a_{1}, a_{2}, . . ., a_{101}

a_{1} = b_{1}

a_{51} = b_{51} .

t = b_{1} + b_{2} + \dots + b_{51} and s = a_{1} + a_{2} + \dots + a_{51},

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