$6.24 g$ of ethanol are vaporized by supplying $5.89 k j$ of heat energy. What is enthalpy of vaporisation of ethanol?

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Solution

Enthalpy of vaporisation of ethanol will be equal to the heat energy supplied to vaporize $1$ mole of ethanol.
Molecular weight of ethanol $= 46 g$
Given that:-
Amount of heat energy supplied to vaporise $6.24 g$ of ethanol $= 5.89 k J$
Therefore,
Amount of heat energy supplied to vaporise $46 g$ of ethanol $= \frac{5.89}{6.24} \times 46 = 43.42 k J$
Hence the enthalpy of vaporisation of ethanol is $43.42 k J$ .

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