Question

$6(3n-2)-1=\frac{9}{4}$

Given the equation above, what is the value of $3n-2$?

• A. $\frac{5}{12}$
• B. $\frac{13}{24}$
• C. $\frac{7}{4}$
• D. $\frac{13}{4}$

Answer 1

The correct option is B $\frac{13}{24}$

We start by adding 1 to both sides

$6(3n-2)-1+1=\frac{9}{4}+1$

$6(3n-2)=\frac{9}{4}+\frac{4}{4}=\frac{13}{4}$

Next divide both side by 6

$\frac{6(3n-2)}{6}=\frac{\left(\frac{13}{4}\right)}{6}$

$(3n-2)=\frac{13}{4}\times \frac{1}{6}$

$(3n-2)=\frac{13}{24}$

Thus value of (3n-2) is $\frac{13}{24}$