The correct option is D ( 54)^ 82( 6)^ 82× (81)^ 41 =( 6)^ 82× (9^2)^ 41 =( 6)^ 82× (9)^ 82 nbsp; nbsp;( Using (a^m)^n =a^mn) =( 6 × 9)^ 82 nbsp; ...

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Power Rule of Exponents

-6-82×81-41=

Question

$(- 6)^{- 82} \times (81)^{- 41}$ =

(- 36)^{- 41}

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(- 486)^{- 82}

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(- 87)^{- 82}

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(- 54)^{- 82}

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Solution

The correct option is D $(- 54)^{- 82}$
$(- 6)^{- 82} \times (81)^{- 41}$

= $(- 6)^{- 82} \times (9^{2})^{- 41}$

= $(- 6)^{- 82} \times (9)^{- 82}$ $(U s i n g (a^{m})^{n} = a^{m n})$

= $(- 6 \times 9)^{- 82}$ $(U s i n g a^{m} \times b^{m} = (a \times b)^{m})$

= $(- 54)^{- 82}$

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(- 6)^{- 82} \times (81)^{- 41}

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