Question

$(-6{)}^{-82}\times (81{)}^{-41}$ =

• A. $(-36{)}^{-41}$
• B. $(-486{)}^{-82}$
• C. $(-87{)}^{-82}$
• D. $(-54{)}^{-82}$

Answer 1

The correct option is D $(-54{)}^{-82}$

$(-6{)}^{-82}\times (81{)}^{-41}$

=$(-6{)}^{-82}\times (9^2{)}^{-41}$

=$(-6{)}^{-82}\times (9{)}^{-82}$ $\left(Using\right(a^m{)}^n=a^{mn})$

=$(-6\times 9{)}^{-82}$ $(Using{a}^m\times b^m=(a\times b{)}^m)$

=$(-54{)}^{-82}$