Question

A child weighing 30 kg slides down a rope hanging from the branch of a tall tree. If the force of friction acting against him is 2 N, what is the acceleration of the child (Take g = 10m / s.)

Answer 1

Step 1: Given

Mass of child, $m=30kg$

Force of friction, $f=2N$

g = 10m / s

Step 2: Formula used and calculation

Now,

$mg-f=ma$

$\Rightarrow 30\times 10-2=30a$

$\Rightarrow a=\frac{298}{30}$

$\Rightarrow a=9.93m{s}^{-2}$

Hence, acceleration of the child is $9.93m{s}^{-2}$ .